(2x^2-4x)/(x+1)

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Solution for (2x^2-4x)/(x+1) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

(2*x^2-(4*x))/(x+1) = 0

(2*x^2-4*x)/(x+1) = 0

2*x^2-4*x = 0

2*x*(x-2) = 0

x-2 = 0 // + 2

x = 2

2*x*(x-2) = 0

(2*x*(x-2))/(x+1) = 0

( 2*x )

2*x = 0 // : 2

x = 0

( x-2 )

x-2 = 0 // + 2

x = 2

x in { 0, 2 }

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